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When deploying the Steady State Approximation (SSA) to resolve a complex multi-step chemical rate laChemical Kinetics Chemistry Question

Question

When deploying the Steady State Approximation (SSA) to resolve a complex multi-step chemical rate law, which of the following strict calculus conditions is mandatorily applied to the highly reactive, non-accumulating intermediate species $I$?

Answer: C

💡 Solution & Explanation

The core kinetic assumption of the SSA dictates that a wildly unstable intermediate is consumed nearly instantly upon generation. Consequently, its macroscopic absolute concentration remains practically negligible and perfectly constant, allowing the differential to be algebraically set to $\frac{d[I]}{dt} \approx 0$.

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