A parallel reaction generates products B and C from A. It is given that and . Calculate the exact pe — Chemical Kinetics Chemistry Question
Question
A parallel reaction generates products B and C from A. It is given that $k_1 (A \rightarrow B) = 1.26 \times 10^{-4} \text{ s}^{-1}$ and $k_2 (A \rightarrow C) = 3.8 \times 10^{-5} \text{ s}^{-1}$. Calculate the exact percentage yield of product B in the final mixture.
Answer: B
💡 Solution & Explanation
Convert $k_1$ to match the exponent: $k_1 = 12.6 \times 10^{-5} \text{ s}^{-1}$. The total rate constant $k_{total} = (12.6 + 3.8) \times 10^{-5} = 16.4 \times 10^{-5} \text{ s}^{-1}$. The percentage yield of B is $\frac{12.6}{16.4} \times 100\% \approx 76.83\%$.
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