When graphically mapping a generic arbitrary kinetic reaction, an analyst plots the reaction half-li — Chemical Kinetics Chemistry Question
Question
When graphically mapping a generic arbitrary kinetic reaction, an analyst plots the reaction half-life ($t_{1/2}$) on the vertical y-axis directly against the absolute inverse of the initial reactant concentration ($1/[A]_0$) on the horizontal x-axis, strictly yielding a straight line projecting cleanly through the absolute origin. Deduce the reaction order.
💡 Solution & Explanation
The universally generalized formula connecting half-life dictates $t_{1/2} \propto [A]_0^{1-n}$. If plotting against $1/[A]_0$ (which is identical to $[A]_0^{-1}$) produces a flawless straight line mapping to $y = mx$, then the exponent $(1-n)$ must identically equal $-1$. Resolving $1 - n = -1$ strictly provides $n = 2$.