The experimental half-life period () of the chemical decomposition of an unknown complex compound is — Chemical Kinetics Chemistry Question
Question
The experimental half-life period ($t_{1/2}$) of the chemical decomposition of an unknown complex compound is firmly established as $50 \text{ minutes}$. However, if the initial reactant concentration is deliberately halved in a new trial, the half-life drastically collapses to precisely $25 \text{ minutes}$. What is the order of reaction?
💡 Solution & Explanation
Applying the master proportionality $t_{1/2} \propto [A]_0^{1-n}$. The data rigorously illustrates that as the initial concentration strictly drops by half, the half-life also perfectly drops by half. This clean, direct, 1-to-1 linear proportionality strictly corresponds to $1 - n = 1$, which flawlessly resolves to $n = 0$.