For a highly specific reversible endothermic chemical reaction, the absolute overall enthalpy change — Chemical Kinetics Chemistry Question
Question
For a highly specific reversible endothermic chemical reaction, the absolute overall enthalpy change is measured strictly as $\Delta H = +20 \text{ kJ mol}^{-1}$. If the forward activation energy is $E_{a(f)} = 85 \text{ kJ mol}^{-1}$, calculate the exact backward activation energy $E_{a(b)}$.
Answer: B
💡 Solution & Explanation
The fundamental thermodynamic and kinetic potential energy link dictates that the Enthalpy of reaction $\Delta H = E_{a(f)} - E_{a(b)}$. Substituting the established numeric parameters yields $+20 = 85 - E_{a(b)}$. Rearranging immediately provides $E_{a(b)} = 85 - 20 = 65 \text{ kJ mol}^{-1}$.
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