Consider the elementary reversible first-order opposing reaction . At a state of dynamic equilibrium, how is the absolute thermodynamic equilibrium constant () mathematically linked to the specific ki

Question

Consider the elementary reversible first-order opposing reaction $A \rightleftharpoons B$. At a state of dynamic equilibrium, how is the absolute thermodynamic equilibrium constant ($K_{eq}$) mathematically linked to the specific kinetic rate constants $k_f$ and $k_b$?

Prashant Kotian · Accepted Answer

Correct answer: D. At dynamic equilibrium, the macroscopic rate of the forward reaction strictly equals the rate of the reverse decay: . Rearranging this kinetic equality perfectly yields the thermodynamic constant: .

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