Consider the elementary reversible first-order opposing reaction . At a state of dynamic equilibrium — Chemical Kinetics Chemistry Question

💡 Solution & Explanation

At dynamic equilibrium, the macroscopic rate of the forward reaction strictly equals the rate of the reverse decay: $k_f[A]_{eq} = k_b[B]_{eq}$. Rearranging this kinetic equality perfectly yields the thermodynamic constant: $K_{eq} = \frac{[B]_{eq}}{[A]_{eq}} = \frac{k_f}{k_b}$.