For a reaction , when is doubled (keeping constant), the rate strictly doubles. When both and are do — Chemical Kinetics Chemistry Question
Question
For a reaction $A + B \rightarrow P$, when $[A]$ is doubled (keeping $[B]$ constant), the rate strictly doubles. When both $[A]$ and $[B]$ are doubled simultaneously, the overall rate increases by a factor of exactly 8. What is the total overall order of this reaction?
Answer: C
💡 Solution & Explanation
Rate = $k[A]^x[B]^y$. Since doubling $[A]$ doubles the rate, $x=1$. Doubling both gives $8 = 2^1 \cdot 2^y \Rightarrow 2^y = 4 \Rightarrow y=2$. The overall order is $x + y = 1 + 2 = 3$.
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