In the pseudo-first-order acid-catalyzed hydrolysis of an ester, reaction progress is monitored by t — Chemical Kinetics Chemistry Question
Question
In the pseudo-first-order acid-catalyzed hydrolysis of an ester, reaction progress is monitored by titrating reaction aliquots against $NaOH$. If $V_0$, $V_t$, and $V_\infty$ are the base volumes required at times zero, $t$, and infinity, the correct analytical rate constant expression is:
💡 Solution & Explanation
The total initial concentration of ester ($a$) is strictly proportional to the total acid generated, $(V_\infty - V_0)$. The unreacted ester remaining at time $t$, $(a-x)$, is proportional to the acid yet to be generated, $(V_\infty - V_t)$. Thus, $k = \frac{2.303}{t} \log\left(\frac{V_\infty - V_0}{V_\infty - V_t}\right)$.