An experimental kineticist plots the inverse of the remaining reactant concentration, , on the y-axi — Chemical Kinetics Chemistry Question
Question
An experimental kineticist plots the inverse of the remaining reactant concentration, $\frac{1}{[A]_t}$, on the y-axis against time $t$ on the x-axis, strictly yielding a perfect straight line with a positive slope. What is the overall kinetic order of this reaction?
Answer: C
💡 Solution & Explanation
The integrated rate law for a pure second-order reaction is $\frac{1}{[A]_t} = \frac{1}{[A]_0} + kt$. This perfectly matches the linear equation $y = c + mx$, where the plotted slope is identically equal to the positive rate constant $+k$.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes