In a pure zero-order reaction, the time required for 50% completion is precisely 100 minutes. What w — Chemical Kinetics Chemistry Question

💡 Solution & Explanation

For a zero-order reaction, the amount reacted $x = kt$. At 50%, $0.5a = k(100)$. At 75%, $0.75a = k(t_{75\%})$. Dividing the equations: $0.75 / 0.50 = t_{75\%} / 100 \Rightarrow 1.5 = t_{75\%} / 100 \Rightarrow t_{75\%} = 150 \text{ minutes}$.