A chemical reaction follows the empirical rate law: . If the initial concentrations of both reactant — Chemical Kinetics Chemistry Question
Question
A chemical reaction $A + B \rightarrow C$ follows the empirical rate law: $\text{Rate} = k[A]^{1/2}[B]^2$. If the initial concentrations of both reactants $A$ and $B$ are simultaneously increased by a factor of 4, by what overall factor will the initial rate of the reaction increase?
Answer: C
💡 Solution & Explanation
The new rate is $r_{new} = k(4[A])^{1/2}(4[B])^2 = k \cdot 4^{1/2} \cdot 4^2 \cdot [A]^{1/2}[B]^2 = 2 \cdot 16 \cdot r_{initial} = 32 \cdot r_{initial}$. The rate increases by a factor of 32.
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