Four moles of are mixed with four moles of for the reaction . At equilibrium, 2 moles of are formed. — Chemical Equilibrium Chemistry Question
Question
Four moles of $A$ are mixed with four moles of $B$ for the reaction $A + B \rightleftharpoons C + D$. At equilibrium, 2 moles of $C$ are formed. The equilibrium constant $K_c$ is:
Answer: B
💡 Solution & Explanation
Init: $A=4$, $B=4$. Eq: $C=2$, so $D=2$, meaning 2 moles of $A$ and $B$ reacted. Eq moles: $A = 4-2=2$, $B = 4-2=2$. $K_c = ([C][D]) / ([A][B]) = (2 \times 2) / (2 \times 2) = 4/4 = 1$.
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