Given: (i) (ii) (iii) What is for ? — Chemical Equilibrium Chemistry Question
Question
Given: (i) $N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g) \quad K_1$ (ii) $N_2(g) + O_2(g) \rightleftharpoons 2NO(g) \quad K_2$ (iii) $H_2(g) + \frac{1}{2}O_2(g) \rightleftharpoons H_2O(g) \quad K_3$ What is $K_4$ for $2NH_3(g) + \frac{5}{2}O_2(g) \rightleftharpoons 2NO(g) + 3H_2O(g)$?
Answer: B
💡 Solution & Explanation
Reverse (i) giving $1/K_1$. Keep (ii) giving $K_2$. Multiply (iii) by 3 giving $K_3^3$. Add them: $(1/K_1) \times K_2 \times K_3^3 = (K_2 K_3^3) / K_1$.
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