Densities of diamond and graphite are and respectively. For the transformation , . Which of the foll — Chemical Equilibrium Chemistry Question
Question
Densities of diamond and graphite are $3.5\text{ g/mL}$ and $2.3\text{ g/mL}$ respectively. For the transformation $C(\text{diamond}) \rightleftharpoons C(\text{graphite})$, $\Delta_r H = -1.9\text{ kJ/mol}$. Which of the following conditions strictly favour the formation of diamond?
Answer: C
💡 Solution & Explanation
Diamond formation is the reverse reaction (endothermic, $\Delta H = +1.9\text{ kJ/mol}$), favoured by high temperature. Diamond has higher density (lower volume). By Le-Chatelier's principle, high pressure shifts equilibrium to the state with lesser volume (diamond). Thus, High P, High T.
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