Why does phosphine () exhibit an bond angle of approximately , severely deviated from the expected t — Chemical Bonding Chemistry Question

💡 Solution & Explanation

Drago's Rule dictates that elements of the 3rd period and beyond (P, S) do not undergo hybridization when bonding to H. They use pure, orthogonal p-orbitals ($p_x, p_y, p_z$), resulting in bond angles near $90^\circ$.