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According to Bent's Rule, where will the lone pairs and highly electronegative fluorine atoms positiChemical Bonding Chemistry Question

Question

According to Bent's Rule, where will the lone pairs and highly electronegative fluorine atoms position themselves in a trigonal bipyramidal ($sp^3d$) geometry like $PCl_3F_2$?

Answer: C

💡 Solution & Explanation

Bent's Rule states that more electronegative atoms (like F) prefer orbitals with less s-character (axial positions, $pd_{z^2}$). Lone pairs demand more space and prefer orbitals with more s-character (equatorial positions, $sp^2$).

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