According to Bent's Rule, where will the lone pairs and highly electronegative fluorine atoms positi — Chemical Bonding Chemistry Question
Question
According to Bent's Rule, where will the lone pairs and highly electronegative fluorine atoms position themselves in a trigonal bipyramidal ($sp^3d$) geometry like $PCl_3F_2$?
Answer: C
💡 Solution & Explanation
Bent's Rule states that more electronegative atoms (like F) prefer orbitals with less s-character (axial positions, $pd_{z^2}$). Lone pairs demand more space and prefer orbitals with more s-character (equatorial positions, $sp^2$).
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