The hybridization states of the central nitrogen atoms in , , and are respectively: — Chemical Bonding Chemistry Question

💡 Solution & Explanation

Using steric numbers: $NO_2^+$ forms 2 $\sigma$ bonds with 0 lone pairs ($S.N.=2 \rightarrow sp$). $NO_3^-$ forms 3 $\sigma$ bonds with 0 lone pairs ($S.N.=3 \rightarrow sp^2$). $NH_4^+$ forms 4 $\sigma$ bonds with 0 lone pairs ($S.N.=4 \rightarrow sp^3$).