Determine the exact number of and bonds present in a single molecule of tetracyanoethylene, . — Chemical Bonding Chemistry Question

💡 Solution & Explanation

The structure is $(N \equiv C)_2C=C(C \equiv N)_2$. The central $C=C$ provides 1 $\sigma$, 1 $\pi$. Four single $C-C$ bonds provide 4 $\sigma$. Four $C \equiv N$ triple bonds provide 4 $\sigma$, 8 $\pi$. Total = $1+4+4 = 9 \sigma$ and $1+8 = 9 \pi$.