The central iodine atom in iodine heptafluoride () undergoes hybridization. What is the resulting mo β Chemical Bonding Chemistry Question
Question
The central iodine atom in iodine heptafluoride ($IF_7$) undergoes $sp^3d^3$ hybridization. What is the resulting molecular geometry?
Answer: C
π‘ Solution & Explanation
Iodine has 7 valence electrons and forms 7 bonds with F (0 lone pairs). Steric number = 7 ($sp^3d^3$). This perfectly symmetrical arrangement yields a pentagonal bipyramidal geometry with $72^\circ$ equatorial and $90^\circ$ axial angles.
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