D-Glucose reacts directly with anhydrous methanol in the presence of dry gas to selectively yield me — Biomolecules Chemistry Question

💡 Solution & Explanation

The reaction with methanol exclusively targets the C1 hemiacetal, replacing the $-OH$ with $-OCH_3$ to form an acetal (glycosidic bond). Because the anomeric carbon is fully "locked" in this ether-like linkage, the ring cannot open, preventing mutarotation and rendering them completely non-reducing.