What is the exact ratio of the de-Broglie wavelengths for identical electrons accelerated from rest — Atomic Structure Chemistry Question

💡 Solution & Explanation

For a charged particle, wavelength $\lambda \propto 1/\sqrt{V}$. The ratio $\lambda_1 / \lambda_2 = \sqrt{V_2 / V_1} = \sqrt{50 / 200} = \sqrt{1/4} = 1/2$. Thus, the ratio is $1 : 2$.