The ionization energy for a hydrogen atom is . The required energy to excite it from the ground stat β Atomic Structure Chemistry Question
Question
The ionization energy for a hydrogen atom is $13.6 \text{ eV}$. The required energy to excite it from the ground state to the next higher state (first excited state) will be:
Answer: B
π‘ Solution & Explanation
The energy of the ground state ($n=1$) is $-13.6 \text{ eV}$ and the first excited state ($n=2$) is $-3.4 \text{ eV}$. The excitation energy is $\Delta E = -3.4 - (-13.6) = 10.2 \text{ eV}$.
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