Uncertainty in the position of an electron moving with a velocity of accurate up to will be (, ): — Atomic Structure Chemistry Question

💡 Solution & Explanation

First find $\Delta v = 0.001\% \text{ of } 300 = \frac{0.001}{100} \times 300 = 0.003 \text{ m/s}$. Apply $\Delta x = \frac{h}{4\pi m \Delta v} = \frac{6.63 \times 10^{-34}}{4 \times 3.14 \times 9.1 \times 10^{-31} \times 0.003} = 1.93 \times 10^{-2} \text{ m}$.