If the kinetic energy of a moving proton is increased to times its initial value, the wavelength of — Atomic Structure Chemistry Question

💡 Solution & Explanation

$\lambda = \frac{h}{\sqrt{2m(K.E.)}}$. Thus $\lambda \propto 1/\sqrt{K.E.}$. If K.E. becomes $9$ times, the new wavelength becomes $1/\sqrt{9} = 1/3$ times the original.