The potential energy of an electron in the second orbit of is . What is the double of the total ener — Atomic Structure Chemistry Question
Question
The potential energy of an electron in the second orbit of $He^+$ is $-27.2 \text{ eV}$. What is the double of the total energy of an electron in the first excited state of a Hydrogen atom?
Answer: B
💡 Solution & Explanation
The total energy of an H-atom in the 1st excited state ($n=2$) is $-13.6 / 2^2 = -3.4 \text{ eV}$. The double of this total energy is exactly $-6.8 \text{ eV}$.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes