The approximate size (radius) of the nucleus of an () atom is: | Atomic Structure — Chem-Mantra

Question

The approximate size (radius) of the nucleus of an $^{64}Ni$ ($Z=28$) atom is:

Answer: B

💡 Solution & Explanation

Nuclear radius $R = R_0 \cdot A^{1/3}$. Here $A = 64$, so $A^{1/3} = 4$. Assuming $R_0 \approx 1.3 \text{ fm}$, $R = 1.3 \times 4 = 5.2 \text{ fm}$.

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