Based on quantum mechanical formulations, the orbital angular momentum of an electron residing in a β Atomic Structure Chemistry Question
Question
Based on quantum mechanical formulations, the orbital angular momentum of an electron residing in a $3p$ orbital is:
Answer: D
π‘ Solution & Explanation
Orbital angular momentum is given by $\sqrt{l(l+1)} \frac{h}{2\pi}$. For any $p$ -orbital, $l=1$. Thus, momentum = $\sqrt{1(1+1)} \frac{h}{2\pi} = \sqrt{2} \frac{h}{2\pi}$.
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