What is the exact ratio of the minimum frequency of the Lyman series to that of the Balmer series? — Atomic Structure Chemistry Question

💡 Solution & Explanation

Minimum frequency corresponds to the longest wavelength transition. Lyman ($n=2 \to 1$) $\propto R(1 - 1/4) = 3R/4$. Balmer ($n=3 \to 2$) $\propto R(1/4 - 1/9) = 5R/36$. Ratio = $(3/4) / (5/36) = 27/5 = 5.4$.