The ionization potential of a single-electron species is exactly . The atomic number () of this spec — Atomic Structure Chemistry Question

💡 Solution & Explanation

The ionization energy of a single-electron species is $13.6 \times Z^2 \text{ eV}$. Setting $340 \text{ eV} = 13.6 \times Z^2$ gives $Z^2 = 340 / 13.6 = 25$. Therefore, $Z = 5$.