The difference in radii of two Bohr orbits of an H-atom is exactly . The corresponding orbits are: — Atomic Structure Chemistry Question

💡 Solution & Explanation

Radius $r_n = 0.529 \times n^2 \text{ \AA}$. The difference $\Delta r = 0.529 \times (n_1^2 - n_2^2) = 24 \times 0.529$. Thus, $n_1^2 - n_2^2 = 24$. This is perfectly satisfied by $n_1=5$ ($25$) and $n_2=1$ ($1$).