The approximate size (radius) of the nucleus of an () atom is: — Atomic Structure Chemistry Question

💡 Solution & Explanation

Nuclear radius $R = R_0 \cdot A^{1/3}$. Here $A = 64$, so $A^{1/3} = 4$. Assuming $R_0 \approx 1.3 \text{ fm}$, $R = 1.3 \times 4 = 5.2 \text{ fm}$.