When a pure secondary () amine is thoroughly subjected to Hinsberg's test (reaction with benzenesulp — Amines Chemistry Question

💡 Solution & Explanation

A $2^\circ$ amine reacts to generate an N,N-dialkylbenzenesulphonamide. Because the nitrogen is fully alkylated, it totally lacks any remaining acidic $N-H$ protons. Consequently, it cannot react with the strong $KOH$ base and remains a water-insoluble solid.