When a pure secondary () amine is thoroughly subjected to Hinsberg's test (reaction with benzenesulp — Amines Chemistry Question
Question
When a pure secondary ($2^\circ$) amine is thoroughly subjected to Hinsberg's test (reaction with benzenesulphonyl chloride followed by excess $KOH$), what is observed?
Answer: B
💡 Solution & Explanation
A $2^\circ$ amine reacts to generate an N,N-dialkylbenzenesulphonamide. Because the nitrogen is fully alkylated, it totally lacks any remaining acidic $N-H$ protons. Consequently, it cannot react with the strong $KOH$ base and remains a water-insoluble solid.
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