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When an aliphatic primary amide, such as propanamide (), is treated with a powerful reducing agent lAmines Chemistry Question

Question

When an aliphatic primary amide, such as propanamide ($CH_3CH_2CONH_2$), is treated with a powerful reducing agent like $LiAlH_4$ followed by hydrolysis, what is the precise structure of the resulting primary amine?

Answer: B

💡 Solution & Explanation

Reduction of a primary amide strictly utilizing $LiAlH_4$ converts the carbonyl group ($-C=O$) directly into a saturated methylene group ($-CH_2-$) without altering the carbon skeleton. Therefore, the 3-carbon propanamide is cleanly reduced, retaining all three carbons, to yield the 3-carbon propan-1-amine.

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