AmineshardMCQ SINGLE⭐ Must-Do

Consider the precise multi-step chemical conversion starting from Propionic acid (). It is heated heAmines Chemistry Question

Question

Consider the precise multi-step chemical conversion starting from Propionic acid ($CH_3CH_2COOH$). It is heated heavily with $SOCl_2$ to form A. 'A' reacts fiercely with excess $NH_3$ to form B. 'B' is extensively treated with a heated mixture of $Br_2$ and $KOH$ to form the final major organic product C. Identify C.

Answer: B

💡 Solution & Explanation

Propionic acid plus $SOCl_2$ yields propanoyl chloride (A). Reaction with $NH_3$ undergoes nucleophilic acyl substitution yielding propanamide (B, 3 carbons). Treatment of B with $Br_2/KOH$ triggers the classical Hofmann bromamide degradation, decisively excising the carbonyl carbon entirely to step down the chain, yielding the 2-carbon primary amine, ethanamine (C).

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry