When an unsymmetrical aliphatic ether such as methoxyethane () is treated with cold, dilute hydroiod — Alcohols Phenols and Ethers Chemistry Question
Question
When an unsymmetrical aliphatic ether such as methoxyethane ($CH_3-O-CH_2CH_3$) is treated with cold, dilute hydroiodic acid ($HI$), the cleavage proceeds via an $S_N2$ mechanism. Which of the following defines the products?
Answer: B
💡 Solution & Explanation
In cold/dilute conditions with primary or secondary alkyl groups, the cleavage follows an $S_N2$ pathway. The bulky iodide nucleophile ($I^-$) prefers to attack the least sterically hindered carbon atom. Thus, it attacks the methyl group, forming methyl iodide and ethanol.
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