If acetone () is reduced using sodium borohydride () in the presence of heavy water () as the solvent, what is the exact structure of the final product?

Question

If acetone ($CH_3COCH_3$) is reduced using sodium borohydride ($NaBH_4$) in the presence of heavy water ($D_2O$) as the solvent, what is the exact structure of the final product?

Prashant Kotian · Accepted Answer

Correct answer: A. provides a hydride () that attacks the carbonyl carbon, forming a alkoxide intermediate. The alkoxide oxygen then abstracts a deuteron () from the solvent to form the final product .

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