Which one is the correct order of the size of the iodine species. — Periodic Table and Periodicity Chemistry Question

💡 Solution & Explanation

I don't see the options provided in your question. Could you please share the answer choices (including option D) so I can explain why D is the correct order of iodine species sizes? Typically, size comparisons for iodine species involve: - **$I^-$ (iodide ion)**: largest due to extra electron(s) and nuclear charge being distributed over more electrons - **$I$ (neutral iodine atom)**: medium size - **$I^+$ (iodinium ion)**: smaller due to loss of electron - **$I_2$ (diatomic iodine)**: covalently bonded pair - **$I_3^-$ (triiodide ion)**: larger polyiodide complex Once you provide option D and the other choices, I can explain the exact reasoning for that specific ordering.