10 mL of N/2 HCl, 20 mL of N/2 and 30 mL N/3 HNO3are mixed together and solution made to one litre. — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question

💡 Solution & Explanation

On dilution, the resultant normality can be calculated as 1 1 2 2 2 2 1 1 2 1 2 NV N V N N N x x MOLE & EQUIVALENT CONCEPT 46 134. 1L solution of NaOH contains 4.0 g of it. What shall be the difference between molarity and the normality? (a) 0.10 (b) zero (c) 0.05 (d) 0.20 Normality = Valency factor × Molarity For NaOH, valency factor=1 ∴ For NaOH, Normality=Molarity 135. 100 ml of 0.3 N HCl is mixed with 200 ml of 0.6 N H2SO4. The final normality of the resulting solution will be (a) 0.1 N (b) 0.2 N (c) 0.3 N (d) 0.5 N M eq. of HCl 1 30 30 x M eq. of 2 4 0.6 200 12