The reaction, H orOH RCOOR R OH excess RCOOR R OH -> is called — Aldehydes Ketones and Carboxylic Acids Chemistry Question

💡 Solution & Explanation

I need to clarify the reaction shown. Based on the pattern indicated, this appears to be describing an **esterification reaction** where an ester ($RCOOR'$) reacts with an excess of alcohol ($R'OH$) in the presence of an acid or base catalyst. ## Step-by-Step Analysis: **Step 1: Identify the reaction type** When an ester reacts with an alcohol (typically in excess) under acidic or basic conditions, it undergoes **transesterification** (if under acid catalysis) or more commonly under basic conditions, it's called **saponification** followed by esterification, or simply **alcoholysis** of an ester. **Step 2: Mechanism consideration** - If $H^+$ (acid) catalyst: The ester exchanges its alkoxy group with the incoming alcohol → **Transesterification** - If $OH^-$ (base) catalyst with excess alcohol: The ester is hydrolyzed to carboxylate salt, then re-esterifies → **Alcoholysis** or **Transesterification** **Step 3: Most likely answer** Given that this is a standard organic chemistry reaction with a specific name, and the conditions show excess alcohol with either acid or base: **The reaction is called TRANSESTERIFICATION** (also called **Alcoholysis** of ester) In transesterification, the alcohol group of the ester is replaced by another alcohol group: $$RCOOR' + R''OH \xrightarrow{H^+ \text{ or } OH^-} RCOOR'' + R'OH$$ **Why B is correct:** This is the standard nomenclature for an ester reacting with excess alcohol to form a new ester with release of the original alcohol.