At 298 K, the solubility product of is 1 10 x . What will be the solubility of in moles/litre — Ionic Equilibrium Chemistry Question
Question
At 298 K, the solubility product of $PbCl_2$ is 1 10 x . What will be the solubility of $PbCl_2$ in moles/litre
Answer: A
💡 Solution & Explanation
For 2 PbCl , x = 1, y = 2 x y x + y K = x y s sp 6 1 2 3 1 10 = 1 2 s x 6 3 6 10 s 0.25 10 4 x 2 3 s 0.63 10 6.3 10 x x
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