Solubility product of is 4 × 10 –9. Its solubility in moles/litre would be — Ionic Equilibrium Chemistry Question
Question
Solubility product of $BaCl_2$ is 4 × 10 –9. Its solubility in moles/litre would be
Answer: A
💡 Solution & Explanation
For 2 BaCl , x = 1, y = 2 x y x + y K = x y s sp 9 1 2 2 1 4 10 1 2 s x 9 3 4 10 4 s x 3 =10 s
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