The correct representation for solubility product of is — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

# Solubility Product of $SnS_2$ **Step 1: Write the dissolution equilibrium** $$SnS_2(s) \rightleftharpoons Sn^{4+}(aq) + 2S^{2-}(aq)$$ **Step 2: Set up the solubility product expression** The solubility product constant $K_{sp}$ is the product of ion concentrations raised to their stoichiometric coefficients: $$K_{sp} = [Sn^{4+}][S^{2-}]^2$$ **Step 3: Why this is correct** - $SnS_2$ is an ionic compound that dissociates into 1 mole of $Sn^{4+}$ and 2 moles of $S^{2-}$ - The exponent on $[S^{2-}]$ is 2 because the stoichiometric coefficient is 2 - Solid phases are excluded from the $K_{sp}$ expression (their activity = 1) **Answer:** The correct representation is $K_{sp} = [Sn^{4+}][S^{2-}]^2$