The dissociation constant of HCN is 5 × 10 –10. The pH of the solution prepared by mixing 1.5 mole o — Ionic Equilibrium Chemistry Question
Question
The dissociation constant of HCN is 5 × 10 –10. The pH of the solution prepared by mixing 1.5 mole of HCN and 0.15 moles of KCN in water and making up the total volume to 0.5 dm 3 is
Answer: C
💡 Solution & Explanation
The solution of HCN and KCN in water is an acidic buffer. No. of moles 1.5 HCN 3M Total volume 0.5 0.15 KCN 0.3M 0.5 a 10 salt pH = pK + log acid IONIC EQUILIBRIUM 42 10 10 0.3 pH = log 5 10 log 3 x pH = 9.3 1 pH = 9.3 1= 8.3
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes