When copper is treated with a certain concentration of nitric acid, nitric oxide and nitrogen dioxid — Redox Reactions and Volumetric Analysis Chemistry Question
Question
When copper is treated with a certain concentration of nitric acid, nitric oxide and nitrogen dioxide are liberated in equal volumes according to the equation. o xC u yH NO Cu NO NO NO H O -> The coefficients x and y are
💡 Solution & Explanation
3 6 2- 3+ 4 CrO 2Cr Change in oxidation state=6 3 3 V.f Mw = 3 -> >> 111. The equivalent weight of MnSO4 is half its molecular weight when it is converted to (a) Mn2O3 (b) MnO2 (c) 4 MnO (d) 2 4 MnO Ans (b) Sol. 2 - 2- MnSO Mn O MnO MnO MnO 4 3 2 4 4 7 2 4 3 6 Change in oxidation state=4 2 2 V.f >> REDOX REACTIONS 20 112. In the reaction 2 3 2 5 VO Fe O FeO V O -> the eq. wt. of V2O5 is equal to its (a) mol. Wt. (b) mol. wt./8 (c) mol. wt./6 (d) None of these Ans (c) Sol. 2 5 +2 5 2 5 2VO V O Change in oxidation state=5 2 3 V