A gas of volume 100 cc. is kept in a vessel at pressure 104 Pa maintained at temperature 24ºC if now — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

# Solution: Gas Volume Change at Constant Temperature **Given:** - Initial volume: $V_1 = 100$ cc - Initial pressure: $P_1 = 10^4$ Pa - Final pressure: $P_2 = 10^5$ Pa - Temperature: constant (24°C) **Step 1: Identify the applicable law** Since temperature is constant, use **Boyle's Law**: $$P_1V_1 = P_2V_2$$ **Step 2: Rearrange for final volume** $$V_2 = \frac{P_1V_1}{P_2}$$ **Step 3: Substitute values** $$V_2 = \frac{10^4 \times 100}{10^5}$$ $$V_2 = \frac{10^6}{10^5} = 10 \text{ cc}$$ **Answer: The final volume is 10 cc** When pressure increases by a factor of 10 (from $10^4$ to $10^5$ Pa) at constant temperature, the volume decreases inversely by the same factor, reducing from 100 cc to 10 cc. This inverse relationship between pressure and volume is the foundation of Boyle's Law for ideal gases at constant temperature.