The decomposition of to is carried out at 280º C in chloroform. When equilibrium is reached 0.2 mol — Chemical Equilibrium Chemistry Question
Question
The decomposition of $N_2O_4$ to $NO_2$ is carried out at 280º C in chloroform. When equilibrium is reached 0.2 mol of $N_2O_4$ and 2 × 10–3mol of $NO_2$ are present in 2 litre solution. The equilibrium constant for the reaction $N_2O_4$ 2 $NO_2$ is
Answer: C
💡 Solution & Explanation
2 4 3 3 2 2 2 c 2 4 -3 2 c -5 0.2 [N O ] 0.1M 2 2 10 [NO ] 1 10 M 2 [NO ] K = [N O ] (1×10 ) K = 0.1 =1×10 x x Hence, the correct answer is option (c)
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