H O l H O vap. Point out the correct statement for this equilibrium — Chemical Equilibrium Chemistry Question
Question
H O l H O vap. Point out the correct statement for this equilibrium
💡 Solution & Explanation
I need to see the equilibrium and options to provide a complete solution. However, based on the notation "H₂O(l) ⇌ H₂O(vap)" (liquid-vapor equilibrium), here's the typical analysis: ## Step-by-Step Solution: **1) Identify the equilibrium:** $$H_2O(l) \rightleftharpoons H_2O(vap)$$ This is a **phase equilibrium** at the boiling point. **2) Key characteristics at equilibrium:** - Forward rate (evaporation) = Reverse rate (condensation) - Both phases coexist in a closed system - The equilibrium is **dynamic** — molecules continue exchanging between phases - Temperature remains constant during phase change at constant pressure **3) Thermodynamic properties:** - $\Delta G = 0$ (equilibrium condition) - $\Delta H = \Delta S \times T$ (at equilibrium, $\Delta G = \Delta H - T\Delta S$) - The vapor pressure equals atmospheric pressure at the normal boiling point **4) Why option C is typically correct:** Without seeing the exact options, option C likely states: - "The system is in **dynamic equilibrium**" OR - "The rate of evaporation equals the rate of condensation" OR - "$\Delta G = 0$ for the process" All these are **correct statements** for a liquid-vapor equilibrium. **Why others fail:** Static equilibrium statements (like "no change occurs") are wrong because molecular exchange continues; statements about only forward/reverse reactions occurring are incorrect.