The rate constant for forward and backward reactions of hydrolysis of ester are 1.1 × 10–2 and 1.5 × — Chemical Equilibrium Chemistry Question
Question
The rate constant for forward and backward reactions of hydrolysis of ester are 1.1 × 10–2 and 1.5 × 10–3 per minute respectively. Equilibrium constant for the reaction is $CH_3COOC_2H_5$ + $H_2O$ $CH_3COOH$ + $C_2H_5OH$
Answer: D
💡 Solution & Explanation
3 2 5 3 2 5 2 CH COOH C H OH k = ... i CH COOC H H O According to rate law rate of forward reaction f f 3 2 5 2 R =K CH COOC H H O And rate of backward reaction b b 3 2 5 R =K CH COOH C H OH f b n Eq R = R 3 2 5 f b 3 2 5 2 CH COOH C H OH K = = K K CH COOC H H O 2 -3 1.1×10 K= 7.33 1.5×10 equilibrium constant will remain unaltered.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes