A vessel at 1000 K contains with a pressure of 0.5 atm. Some of the is converted to CO on addition of graphite. If the total pressure at equilibrium is 0.8 atm, the value of K is :

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Question

A vessel at 1000 K contains $CO_2$ with a pressure of 0.5 atm. Some of the $CO_2$ is converted to CO on addition of graphite. If the total pressure at equilibrium is 0.8 atm, the value of K is :

Prashant Kotian · Accepted Answer

Correct answer: A. 2 g s g CO +C 2CO 0.5atm 0.5 P 2P Total pressure 0.5 P + 2P = 0.8 Thus P = 0.3 2 P 2 P co K = =1.8atm Pco

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